sat suite question viewer

Problem-Solving and Data Analysis / Percentages Difficulty: Hard

The number of zebras in a population in $2018$ was $1.27$ times the number of zebras in this population in $2014$ . If the number of zebras in this population in $2014$ is $p %$ of the number of zebras in this population in $2018$ , what is the value of $p$ , to the nearest whole number?

Back question 64 of 78 Next

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78

Explanation

The correct answer is $79$ . Let $x$ represent the number of zebras in the population in $2014$ and let $y$ represent the number of zebras in the population in $2018$ . It’s given that the number of zebras in this population in $2018$ was $1.27$ times the number of zebras in this population in $2014$ . It follows that the equation $y equals 1.27 x$ represents this situation. Dividing both sides of this equation by $1.27$ yields $\frac{y}{1.27} = x$ , or $(\frac{1}{1.27}) y = x$ . Therefore, the number of zebras in this population in $2014$ is $StartFraction 1 Over 1.27 EndFraction$ times the number of zebras in this population in $2018$ . If the number of zebras in this population in $2014$ is $p %$ of the number of zebras in this population in $2018$ , then $x = \frac{p}{100} y$ . It follows that $\frac{1}{1.27} = \frac{p}{100}$ , or $\frac{100}{1.27} = p$ , which means $p$ is approximately equal to $78.74$ . Therefore, the value of $p$ , to the nearest whole number, is $79$ .